∵一条渐近线方程为√3X-3Y=0,且焦点在x轴上∴设双曲线方程为3x²-9y²=k (k>0),即x²/(k/3)-y²/(k/9)=1,∵c=3,a²=k/3,b²=k/9,a²+b²=c²,∴k/3+k/9=9,解得k=81/4,故双曲线...