设a1,a2,a3为正数,且a1+a2+a3=1,求证1/(a1)²+1/(a2)²+1/(a3)²≥27
人气:379 ℃ 时间:2020-04-21 00:42:49
解答
a1,a2,a3为整数,
∴1=a1+a2+a3>=3(a1a2a3)^(1/3),
∴a1a2a3<=(1/3)^3=1/27,
∴1/a1^2+1/a2^2+1/a3^2>=3[1/(a1a2a3)^2]^(1/3)>=3(27^2)^(1/3)=27.
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