kx+y+z=1 ①x+ky+z=k ②x+y+kz=k² ③①+②+③得；(k+2)(x+y+z)=k²+k+1x+y+z=(k²+k+1)/(k+2)当k+2=0时；k=-2：(k²+k+1)/(k+2)无意义∴该方程组无解当该方程组左边系数相等,右边值也相等时该方程...