在菱形ABCD中,点E在BC上,若角B等于角EAD等于70度,求角AED,角DEC的度数
人气:358 ℃ 时间:2020-06-11 21:14:05
解答
依题意可得:∠BAD = 180°-∠B = 110° ,
∠BAE = ∠BAD-∠EAD = 40° ,
∠AEB = 180°-∠BAE-∠B = 70° .
则有:∠AEB = ∠B ,可得:AE = AB = AD ,
∠AED = (1/2)(180°-∠EAD) = 55° ,
∠DEC = 180°-∠AEB-∠AED = 55° .
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