连接A1C1,B1D1交于O过E作EF⊥A1C1于F,连接AF正方体∴A1C1⊥B1D1∴EF||B1D1∵E是A1B1中点∴EF=1/2B1O=1/4B1D1=√2/4∵AA1⊥面A1B1C1D1∴AA1⊥EF∴EF⊥面ACC1A1∴∠EAF即直线AE与平面ACC1A1所成角AE=√5/2∴sin∠EAF=...