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tanθ=(sina-cosa)/(sina+cosa) 求sina-cosa/sinθ
人气:181 ℃ 时间:2020-06-23 01:50:20
解答
tanθ=(sina-cosa)/(sina+cosa) =(tana-1)/(tana+1)=tan(a-45°)θ=α-45°或者θ=180°+α-45°=α+135°当θ=α-45°,sina-cosa/sinθ=sina-cosa/1/根号2(sinα-cosα)=根号2当θ=α+135°,sina-cosa/sinθ=si...
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