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tanθ=2,2sin^2θ+3sin2θ+1=?
怎么两个答案不一样啊
人气:308 ℃ 时间:2020-02-05 02:45:20
解答
2sin^2θ+3sin2θ+1=(2sin^2θ+3sin2θ+1)/1=(2sin^2θ+3*2sinθ*cosθ+sin^2θ+cos^2θ)/sin^2θ+cos^2θ=
然后分子,分母,同时除以cos^2θ
=(3tan^2θ+6tanθ+1)/tan^2θ+1=(12+12+1)/5=5
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