n为偶数,a1•an=a2•an-1=a3•an-2=…=a
n |
2 |
n |
2 |
∴中间n个数的积为(
n+1 |
n |
n |
2 |
当n为奇数,a1•an=a2•an-1=a3•an-2=…=(a
n+1 |
2 |
中间n个数的积为
(
n+1 |
n |
n−1 |
2 |
n+1 |
n |
1 |
2 |
n+1 |
n |
n |
2 |
综上所述,结果为(
n+1 |
n |
n |
2 |
故答案为(
n+1 |
n |
n |
2 |
1 |
n |
n |
2 |
n |
2 |
n+1 |
n |
n |
2 |
n+1 |
2 |
n+1 |
n |
n−1 |
2 |
n+1 |
n |
1 |
2 |
n+1 |
n |
n |
2 |
n+1 |
n |
n |
2 |
n+1 |
n |
n |
2 |