f（x）=4cos²wx-4√3sinwx*coswx+b=2（cos2wx+1)-2√3sin2wx+b=2cos2wx-2√3sin2wx+b+2=4cos(2wx+π/3 )+b+2(1)最小正周期T=2π/(2w)=π所以w=1则f（x）=4cos(2x+π/3 )+b+2(2)因-π/3≤x≤π/6所以-π/3≤2x+...