>
数学
>
已知4x-3y-6z=0,x+2y-7z=0,xyz≠0,求
2
x
2
+3
y
2
+6
z
2
x
2
+5
y
2
+7
z
2
的值.
人气:274 ℃ 时间:2019-08-26 05:13:30
解答
4x-3y-6z=0 ①,
x+2y-7z=0 ②,
②×4,得4x+8y-28z=0③,
③-①,得11y-22z=0,即y=2z,
把y=2z代入②得,x+4z-7z=0,即x=3z,
把y=2z,x=3z代入,原式=
2(3z
)
2
+3(2z
)
2
+
6z
2
(3z
)
2
+5(2z
)
2
+7
z
2
=
36
z
2
36
z
2
=1.
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