已知x=根号5-2分之根号5-2,y=根号5+2分之根号5-2.求(1)x+y (2)xy (3)x+y分之x²+3xy+y²
已知x=根号5-2分之根号5+2,y=根号5+2分之根号5-2.求(1)x+y (2)xy (3)x+y分之x²+3xy+y²。(2和-2都在根号外)
人气:373 ℃ 时间:2019-08-19 21:13:36
解答
x=(√5+2)/(√5-2) =(√5+2)²/[(√5-2)(√5+2)] =(9+4√5)/(5-2)=(9+4√5)/3 y=(√5-2)/(√5+2) =(√5-2)²/[(√5-2)(√5+2)] =(9-4√5)/(5-2)=(9-4√5)/3(1)x+y=(9+4√5)/3+(9-4√5)/3 =(9+9)/3 =...x, (√5-2)(√5+2)怎么是(5-2)x=(√5+2)/(√5-2) =(√5+2)²/[(√5-2)(√5+2)] =(9+4√5)/(5-4)=9+4√5 y=(√5-2)/(√5+2) =(√5-2)²/[(√5-2)(√5+2)] =(9-4√5)/(5-4)=9-4√5(1)x+y=(9+4√5)+(9-4√5) =9+9 =18(3)(x²+3xy+y²)/(x+y)=[(x+y)²+xy]/(x+y)=(18²+1)/18=325/18
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