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数学
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若正实数a，b满足ab=2，则（1+2a）（1+b）的最小值为______．
人气：263 ℃ 时间：2020-01-26 03:07:03
解答
∵（1+2a）（1+b）=1+b+2a+2ab=5+b+2a≥5+2
2ab
=9
当且仅当b=2a=1即b=2，a=1时取等号
故答案为：9
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