1+cosx=2cos²(x/2)所以原积分可拆分为两个积分计算S(0-π)(1+cosx)^1/2dx=S(0-π/2)(根号2)cos(x/2)dx+S(π/2-π)(根号2)(-cos(x/2))dx=[2(根号2)sin(x/2)](0-π/2)-[2(根号2)sin(x/2)](π/2-π)=(2根号2)[(sin...