2x-3i=3xi+1
2x-3xi=1+3i
x(2-3i)=1+3i
x=(1+3i)/(2-3i)
x=(1+3i)(2+3i)/(2^2+3^2)=(2-9+9i)/13=(-7+9i)/13=(-7/13)+(9/13)i
x = (-7/13) + (9/13)i