f(x)=(1+4x)^5(3+x-x^2)^8=(4x+1)^5(x^2-x-3)^8.令g(x)=4x+1,h(x)=x^2-x-3.令G(x)=x^5,H(x)=x^8.则f(x)=G(g(x))H(h(x)).则f'(x)=G'(g(x))g'(x)H(h(x))+G(g(x))H'(h(x))h'(x) =5(g(x))^4*4*(h(x))^8+(g(x))^5*8(h(x))...