当m取什么实数时,方程4x^2+(m-2)x+(m-5)=0分别有
(1)两个实根 (2)一正根和一负根 (3)正根绝对值大于负根绝对值 (4)两根都大于1
人气:428 ℃ 时间:2019-10-31 10:05:27
解答
4x^2+(m-2)x+(m-5)=0设此方程的两根分别为x1,x2(1)∵此方程有两个实根∴△=(m-2)^2-4*4(m-5)=m^2-20m+84>0解得m14∴当m14时,方程有两个实根(2)∵此方程有一正根和一负根∴△=(m-2)^2-4*4(m-5)=m^2-20m+84>0x1x2=(m-5...
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