(2x²-3x-ay+6)-(2bx²-3x+3y-1)
=2x²-3x-ay+6-2bx²+3x-3y+1
=2(1-b)x²-（a+3）y+7
由于多项式(2x²-3x-ay+6)-(2bx²-3x+3y-1)的值与x.y的取值无关,
所以1-b=0,a+3=0
b=1,a=-3
(a+b)(a-b)=a²-b²=（-3）²-1²=9-1=8