设A(a²/8,a),B(b²/8,b)
y² = 8x = 2*4x,F(2,0)
AB的方程:(y - b)/(a - b) = (x - b²/8)/(a²/8 - b²/8) = (8x - b²)/(a² - b²)
y - b = (8x - b²)/(a + b)
直线l经过F:-b = (16 - b²)/(a + b)
b = -16/a
B(32/a²,-16/a)
F是缐段AB的一个3等分点,则:
(1) AF = AB/3
(a - 0)/(a + 16/a) = 1/3
a = ±2√2
A(1,2√2):斜率k = (2√2 - 0)/(1 - 2) = -2√2 (