在梯形ABCD中,AD平行EF平行HG平行BC,AE=EG=GB,AD=18,BC=12.则EF+HG等於多少?
人气:343 ℃ 时间:2020-02-02 13:02:33
解答
给你一个最简单的解法:
根据中位线定理,可知:2*EF=AD+HG,2*HG=BC+EF,以上两式相加,化简可得:
EF+HG=AD+BC=18+12=30.解答完毕.
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