> 数学 >
如何推导-√2<sin∠α+cos∠α<√2
人气:432 ℃ 时间:2020-06-22 13:11:24
解答
(sin∠α - cos∠α)^2 >= 0展开移项得:(sin∠α)^2 + (cos∠α)^2 >= 2 * sin∠α * cos∠α不等式两边同时加上(sin∠α)^2 + (cos∠α)^2 ,不等号不变,得:2 * [(sin∠α)^2 + (cos∠α)^2 ] >= (sin∠α + ...
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版