设A(yA^2/2p,yA),B(yB^2/2p,yB),显然yA,yB均不为零由OA垂直OB,我们有(yA^2/2p)*(yB^2/2p)+yA*yB=0,而yAyB不为零,所以得到(yA*yB/4p^2)+1=0,yA*yB=-4p^2,进而xA*xB=(yA^2/2p)*(yB^2/2p)=4p^2