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分解因式:
(1)-2x5n-1yn+4x3n-1yn+2-2xn-1yn+4
(2)x3-8y3-z3-6xyz;
(3)a2+b2+c2-2bc+2ca-2ab;
(4)a7-a5b2+a2b5-b7
人气:412 ℃ 时间:2019-11-09 00:10:39
解答
(1)原式=-2xn-1yn(x4n-2x2ny2+y4)=-2xn-1yn[(x2n)2-2x2ny2+(y2)2]=-2xn-1yn(x2n-y2)2=-2xn-1yn(xn-y)2(xn+y)2.(2)原式=x3+(-2y)3+(-z)3-3x(-2y)(-z)=(x-2y-z)(x2+4y2+z2+2xy+xz-2yz)....
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