方程x(kx+2k)-x²+k+3=0有两个实数根kx²+2kx-x²+k+3=0;(k-1)x²+2kx+k+3=0;∴k-1≠0;Δ=(2k)²-4(k-1)(k+3)=4k²-(4k²+8k-12)=12-8k≥0;∴k≤12/8=3/2;且k≠1；∴k最大整数解为0；您...