tanx+tan(3/2π-x)
=tanx+ctgx
=sinx/cosx +cosx/sinx
=1/sinx*cosx
原式=sinx+sin(x-π/2)=根号2
(sinx-cosx)平方=2
1-2*sinx*cosx=2
sinx*cosx=-1/2
所以tanx+tan(3/2π-x) =-2