方程lx+1l+l2x-1l=1的整数解的个数为（ 0 ）个当x>0时lx+1l>1,lx+1l+l2x-1l>1得方程lx+1l+l2x-1l=1无实数解当x=0时,lx+1l+l2x-1l>=2≠1得0不是方程lx+1l+l2x-1l=1的解当x1,lx+1l+l2x-1l>1得方程lx+1l+l2x-1l=1无实数...