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数学
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复数z满足(1-i)z=(1+i)的平方 则z=?
人气:258 ℃ 时间:2020-05-20 08:38:52
解答
设z=x+yi,则(1-i)z=(1-i)(x+yi)=x+y+(y-x)i=(1+i)^2=2i,
所以x+y=0 y-x=2 解得x=-1,y=1
所以z=-1+i
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