y=(3sinx)/(2sin x+√3)
3sinx=2ysinx+√3y
sinx=√3y/(3-2y)-1<=sinx<=1
-1<=√3y/(3-2y) <=1
-1<=√3y/(3-2y)解得 y>=6+3√3或y<3/2
√3y/(3-2y) <=1 解得y>3/2或y<=6-3√3
值域为y>=6+3√3或y<=6-3√3