设这40个数据为x1,x2,…,x40,则(x1+x2+…+x40)/40=2,∴x1+x2+…+x40=80方差s²=[(x1-2)²+(x2-2)²+…+(x40-2)²]/40=[(x1²-4x1+4)+(x2²-4x2+4)+…+(x40²-4x40+4)]/40=[(x1²+x2...