∵lim(x→-1)（ x³-ax²-x+4）/（x+1）=l∴x^3-ax^2-x+4能被x+1整除.∴（ x³-ax²-x+4）=(x+1)[x²-(a+1)x+4]∴-(a+1)x+4x=-x∴3-a=-1,a=4∴lim(x→-1)（ x³-ax²-x+4）/（x+1）=lim...