根据题设按部就班因为a△b=1/(a+b)a※b=b/（a^2-b^2),所以：m△n+2（m※n）=1/（m+n+2)+2n/（m²-n²）通分=(m²-n²+2mn+2n²+4n)/(m²-n²)(m+n+2)=(m²+n²+2mn+4n)/(m²...