根据等比数列规律am*an = a(m+n)/2 ^2 (比如a1*a3=a2^2)
a(n+1)为中间项,
奇数项有n+1项,偶数项为n项,得到奇数项之积=偶数项之积*a(n+1)
举个例子(a1*a3*a7*a9)*a5=a2*a4*a6*a8 *a5
a（n十1）=100/120=5/6