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求证tan^x-sin^2x=tan^2x*sin^2x
人气:280 ℃ 时间:2020-02-06 06:57:57
解答
tan^x-sin^2x
=sin^2x/cos^2x -sin^2x
=(sin^2x-cos^2x sin^2x)/cos^2x
=sin^2x(1-cos^2x)/cos^2x
=sin^2x sin^2x/cos^2x
=tan^2x sin^2x=右边
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