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设f(n)=1/(n+1)+1/(n+2)+.+1/(n+2^n),则f(k+1)-f(k)=
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人气:165 ℃ 时间:2020-03-27 13:24:21
解答
f(k)=1/(k+1)+1/(k+2)+...+1/(k+2^k)f(k+1)=1/(k+2)+1/(k+3)+...+1/(k+2^k)+...+1/[k+1+2^(k+1)]所以:f(k+1)-f(k)=1/(k+1+2^k)+1/(k+2+2^k)+...+1/[k+1+2^(k+1)]-1/(k+1)
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