已知sin2a^2+sin2acosa-cos2a=1,a属于(0,π/2),求sina,tana
人气:273 ℃ 时间:2020-03-13 18:27:11
解答
原题是不是这样的(sin2a)^2+sin2acosa-cos2a=1如果是的话,解如下:(2SinaCosa)^2 +2Sina(Cosa)^2-{[2(Cosa)^2]-1}=14[(Sina)^2][(Cosa)^2] + 2Sina(Cosa)^2 - 2(Cosa)^2 = 02[(Sina)^2] + Sina - 1= 0Sina=-1或1/2...
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