观察下列各式,1/6=1/2*3=1/2-1/3;1/12=1/3*4=1/3-1/4:1/20=1/4*5=1/4-1/5;1/_数学解答

观察下列各式,1/6=1/2*3=1/2-1/3;1/12=1/3*4=1/3-1/4:1/20=1/4*5=1/4-1/5;1/30=1/
用上面的规律解方程：1/（x-2)（x-3)-1/(x-1)(x-3)+1/(x-1)(x-2)
不要用其他人的回答,

人气：465 ℃　时间：2020-04-18 14:12:10

解答

1/（x-2)（x-3)-1/(x-1)(x-3)+1/(x-1)(x-2)
=1/（x-2)-1/（x-3)-1/(x-1)+1/(x-3)+1/(x-1)-1/(x-2)
=01/(x-1)(x-3)怎么化成1/(x-1)+1/(x-3）还有1/(x-1)(x-2)应该是)1/(x-2)-1/(x1)吧，1/(x-2)小于1/(x1)，不是要放在前面吗哦，对不起 1/（x-2)（x-3)-1/(x-1)(x-3)+1/(x-1)(x-2) =1/（x-3)-1/（x-2)-1/2[1/(x-3)-1/(x-1)]+1/(x-2)-1/(x-1) =1/（x-3)-1/（x-2)-1/2(x-3)+1/2(x-1)+1/(x-2)-1/(x-1) =1/2(x-3)-1/2(x-1) =1/(x-1)(x-3)