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求不定积分:∫[f(x)/f′(x)-f²(x)f″(x)/f′(x)³]dx
人气:100 ℃ 时间:2020-03-21 12:09:27
解答
∫[ƒ(x)/ƒ'(x) - ƒ(x)²ƒ''(x)/ƒ'(x)³] dx=∫[f(x)/f′(x)]•(f′(x)²-ƒ(x)²ƒ''(x))/ƒ'(x)²)dx=∫[f(x)/f′(x)]•(f(x)/ƒ'(x))′d...
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