c(HAc)=0.001mol/lHAc溶液的PH值；（Ka=0.00018)_化学解答

c(HAc)=0.001mol/lHAc溶液的PH值；（Ka=0.00018)

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解答

[H+] = (cKa)^(1/2) = (0.001*0.00018)^(1/2) = 4.24*10^(-4) mol/L
pH = -log[H+] =3.37