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求和1/2!+2/3!+3/4!+……n/(n+1)!
人气:386 ℃ 时间:2020-04-02 09:24:33
解答
1/2!+2/3!+3/4!+……n/(n+1)!
=(1/1-1/2!)+(1/2!-1/3!)+(1/3!-1/4!)+...+[1/n!-1/(n+1)!]
=1-1/(n+1)!
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