((a+1)x-3)/(x-1)＜x-a→[((a+1)x-3)-(x-a)(x-1)]/(x-1)＜0→(-x^2+2(a+1)x-a-3)/(x-1)＜0对任意x>1恒成立∴-x^2+2(a+1)x-a-3＜0,x>1恒成立令g(x)=-x^2+2(a+1)x-a-3当对称轴x=a+1＞1,即a＞0时,则要求g(a+1)=a^2-a-2...