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(tanx)^[1/(cosx-sinx)]当x
人气:135 ℃ 时间:2020-05-08 16:12:08
解答
洛必达法则
原式=lim(x趋于π/4)e^[lntanx/(cosx-sinx)]
=lim(x趋于π/4)e^[(1/cos^2xtanx)/(-sinx-cosx)]
=lim(x趋于π/4)e^1/[-sinxcosx(sinx+cosx)]
=e^(-√2)
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