mn-1=2sinx*√3cosx+cosx*2cosx-1=2√3sinxcosx+2cos^2x-1=√3sin2x+cos2x=2(sin2xcosπ/6+cos2xsinπ/6)=2sin(2x+π/6)loga(mn-1)=loga[2sin(2x+π/6)]所以最小正周期为2π/2=π当a>1,则当2sin(2x+π/6)单调增时f(x...