求该函数的间断点,并判断其类型.f(x)=arctan(1/x^2-3x+2)?_数学解答

求该函数的间断点,并判断其类型.f(x)=arctan(1/x^2-3x+2)?

人气：112 ℃　时间：2020-03-31 20:52:59

解答

x^2-3x+2 = (x-1)(x-2) = 0=> x=1,x=2x->1- ,1/( x^2-3x+2) -> +∞, arctan(1/x^2-3x+2) -> π/2x->1+ ,1/( x^2-3x+2) -> -∞, arctan(1/x^2-3x+2) -> -π/2=》 x=1 为第一类跳跃间断点x->2- ,1/( x^2...