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(2sin^x+sin2x)/(1+tanx)化简
人气:435 ℃ 时间:2020-05-08 02:46:47
解答
(2sin^x+sin2x)/(1+tanx)
=(2sinx^2+2sinxcosx)/(1+sinx/cox)
=2sinx(sinx+cosx)/[(sinx+cosx)/cosx]
=2sinxcosx
=sin2x.
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