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∫1/(1+cos^2(x)) dx
人气:432 ℃ 时间:2020-05-26 11:58:07
解答
∫dx/{1+[cos(x)]^2}= ∫[sec(x)]^2dx/{1+[sec(x)]^2}= ∫[sec(x)]^2dx/{2+ [tan(x)]^2}= ∫2^(-1/2)d[tan(x)/2^(1/2)]/{1+ [tan(x)/2^(1/2)]^2}= 2^(-1/2)arctan[tan(x)/2^(1/2)] + CC 为任意常数.
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