证明：(tanA-secA+1)/(secA-tanA+1)=(tanA+secA-1)/(tanA+secA+1)_数学解答

证明：(tanA-secA+1)/(secA-tanA+1)=(tanA+secA-1)/(tanA+secA+1)

人气：138 ℃　时间：2020-09-12 17:59:51

解答

(tanA-secA+1)/(secA-tanA+1)=(sinA-1+cosA)/(1-sinA+cosA)(tanA+secA-1)/(tanA+secA+1)=(sinA+1-cosA)/(sinA+1+cosA)∵(1-sinA+cosA)(sinA+1-cosA)=1-(sinA-cosA)²=1-(sin²A+cos²A-2sinAcosA)=1-(1-...