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设集合A={x│x2-(a+2)x+2a
人气:271 ℃ 时间:2020-06-02 18:16:44
解答
x^2-(a+2)x+2a<0,
[x-(a+2)/2]^2+2a-a^2/4-a-1<0
[x-(a+2)/2]^2-(a^2/4-a+1)<0
[x-(a+2)/2]^2<[(a-2)/2]^2
若a>=2,则-(a-2)/2若a<2,则(a-2)/2所以a<=3
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