y=[e^x-e^(-x)]/[e^x+e^(-x)]=(e^(2x)-1]/[e^(2x)+1]反解得 e^(2x)=(1+y)/(1-y)两边取对数得 2x=ln[(1+y)/(1-y]故x=ln√[(1+y)/(1-y)]交换x,y,便得反函数 y=ln√[(1+x)/(1-x)]由(1+x)/(1-x)≥0,得(x+1)/(x-1)≤0,故 ...