是x(n+1) = Ax(n) + B吗?若是的话,A=1时,x(n+1) = x(n) + B,{x(n)}是首项为x(1), 公差为B的等差数列.x(n) = x(1) + (n-1)B.A不为1时,x(n+1) = Ax(n) + B,x(n+1) + B/(A-1) = Ax(n) + B + B/(A-1) = Ax(n) + AB/(A-1)...