(1)向量a丄向量b∴√3sin2x+cos2x=02sin(2x+兀/3)=0x=兀/3(2)f(x)=向量a*向量b-1=√3sin2x+cos2x-1=2sin(2x+兀/3)-1X属于[0,兀/2]∴2x+兀/3∈[兀/3,4兀/3]∴f(x)∈[-√3-1,1](3)|向量a+向量b|=根号下（sin2x+√3)
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