π
(2)√2+1 {x|x=π/8+kπ ,k∈Z}
(3)[π/8,5π/8]求过程阿谢谢><
将已知条件代入f(x),解得a=1,b=2,
f(x)=√2sin(2x+π/4)+1
最小正周期T=2π/2=π
f(x)max=√2+1 2x+π/4=π/2+2kπ {x|x=π/8+kπ ,k∈Z}
2x+π/4∈[-π/2+2kπ ，π/2+2kπ ]
x∈[π/8，5π/8]
将已知条件代入f(x),解得a=1,b=2,
f(x)=√2sin(2x+π/4)+1
最小正周期T=2π/2=π
f(x)max=√2+1 2x+π/4=π/2+2kπ {x|x=π/8+kπ ,k∈Z}
2x+π/4∈[-π/2+2kπ ，π/2+2kπ ]
x∈[π/8，5π/8]